Question

A wire lying along a y axis form y=0 to y=0.25 m carries a current of 2.0 mA in the negative direction of the axis. the wire fully lies in a magnetic field given by (0.3y)i + (0.4y)j Tesla. The magnetic force on the wire is *

Answer 1

The force is "19 µN".

Step-by-step explanation:

The lane's j-component is meaningless, as the current is flowing in the -j line.

Therefore the power is now in the direction of + z (out of the page if x and y are in the page plane) and has the magnitude.

`\ formula: \\\\\ Forec (F) = mA \\\\ \ F \ = 2.0mA * \int {0.3} \ y \ dy \rightarrow \ from\ 0 \ to \ 0.25 \\\\\ F \ = \ 2.0mA * 0.15 * 0.25^(2) m\cdot T \\\\ F = 19 \µN`