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How many moles of SnF₂ will be produced along with 48 grams of H₂? *

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12 moles
24 moles
48 moles
96 moles

User OClyde
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1 Answer

5 votes

Answer:

The correct option is;

24 moles

Step-by-step explanation:

Here, we have the reaction as follows;

Sn(s) + 2HF(g) → SnF₂ (s) + H₂ (g)

Therefore, one mole of Sn reacts with 2 moles HF to form one mole of SnF₂ and one mole of H₂

Molar mass of H₂ = 2.01588 g/mol

Therefore, the number of moles of H₂ in 48 grams of H₂ is given by the relation;


Number \ of \ moles \ of \, H_2 = (Mass \ of H_2)/(Molar \ Mass \ of H_2)=(48)/(2.01588) = 23.8109 \ moles \approx 24 \ moles

Since one mole each of SnF₂ and H₂ are produced, the number of moles of SnF₂ produced = 24 moles.

The number of moles of SnF₂ that will be produced is 24 moles.

User Grimless
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