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There are 12 red marbles and 8 green marbles in a bag. What is the probability of selecting a red

marble, not replacing it, and then selecting a green marble from the bag?

User Cheik
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1 Answer

3 votes

Answer:

The probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag is 24/95

Explanation:

Number of red marbles = 12

Number of green marbles = 8

Total number of marbles = 12+8 = 20

Probability of selecting red marble =
(12)/(20)

Since it is the case of no replacement

Remaining marbles = 20-1 = 19

Number of red marbles = 12-1=11

Number of green marbles = 8

Probability of selecting green marble =
(8)/(19)

So, the probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag =
(12)/(20) * (8)/(19)=(24)/(95)

Hence the probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag is 24/95

User Ben Anderson
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