Question

There are 12 red marbles and 8 green marbles in a bag. What is the probability of selecting a red

marble, not replacing it, and then selecting a green marble from the bag?

Answer 1

The probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag is 24/95

Explanation:

Number of red marbles = 12

Number of green marbles = 8

Total number of marbles = 12+8 = 20

Probability of selecting red marble =
`(12)/(20)`

Since it is the case of no replacement

Remaining marbles = 20-1 = 19

Number of red marbles = 12-1=11

Number of green marbles = 8

Probability of selecting green marble =
`(8)/(19)`

So, the probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag =
`(12)/(20) * (8)/(19)=(24)/(95)`

Hence the probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag is 24/95