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he complex formsof the sine and cosine functions are:ieexixix2sinand2cosixixeex, where eis the Euler e, and 1i.Differentiate the complex form of cosxto showthatxxdxdsin)(cos.[Hints:The Quotient Rule may be used, but it is not necessaryif you factor out a constant first.√−1=iis a constant. In fact, you can use it to multiply a fraction by iiif that helps...]

User AlMcLean
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Answer:


\cos'(z) = -\sin(z)

Explanation:

According to the information given by the problem


\sin(z) = {\displaystyle (e^(iz) - e^(-iz) )/(2i) }


\cos(z) = {\displaystyle (e^(iz) + e^(-iz) )/(2) }

Now, if you compute the derivative of
\cos you get that


\cos'(z) = {\displaystyle ( ie^(iz)-i e^(iz) )/(2) } = {\displaystyle ( i ( e^(iz)- e^(iz) ))/(2) }\\\\= {\displaystyle ( i ( e^(iz)- e^(iz) ))/(2) } *(i)/(i) }\\\\= {\displaystyle - ( e^(iz)- e^(iz) )/(2i) } = -\sin(z)