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How many moles of gas will occupy 3.5 L container at 315 K, if the pressure is 2.1 atm?

1 Answer

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Answer: 3 moles

Step-by-step explanation:

Using the ideal gas equation; PV = nRT

P= Pressure= 2.1 Atm V= Volume = 3.5L T= Temperature = 315K

n= no of moles

R= Gas constant = 0.08206 L .atm. mol-1 . K-1

Making 'n' the subject of the formular, we then have;

n = PV / RT

= 2.1 Atm x 3.5L / 0.08206 L .atm. mol-1 . K-1 x 315K

= 7.35 / 25.849

= 0.28 approx 3moles

User Doug Johnston
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