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In the figure below. AB is a diameter of circle P.
What is the arc measure of AD in degrees?

User ZioBit
by
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1 Answer

2 votes

Answer:

m Arc AD = 43°

Explanation:

The question is missing a diagram. Find attached the diagram of the question.

Given:

AB is a diameter of circle P

Solution:

From the diagram,

∠ADP = 7x+1

∠BPC = 9x-7

∠CPD = 90° (the symbol of right angle is drawn)

∠m Arc APB = 180° (sum of angles on a straight line or sum of angle in a semi circle)

∠APD + ∠CPD + ∠BPC = 180°

(7x+1)° + 90° + (9x-7)° = 180°

7x+1 + 90 + 9x-7 = 180

Collect like terms

7x+9x = 180 - 90 + 7 -1

16x = 96

x = 96/16

x = 6

Insert the value color x in ∠APD

∠APD = 7(6) + 1

∠APD = 43°

m Arc AD = ∠ APD

m Arc AD = 43°

Therefore arc measure of AD in degrees = 43°

In the figure below. AB is a diameter of circle P. What is the arc measure of AD in-example-1
User Tonga
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