Question

Polarizers #1 and #3 are "crossed" such that their transmission axes are perpendicular to each other. Polarizer #2 is placed between the polarizers #1 and #3 with its transmission axis at 60◦ with respect to the transmission axis of the polarizer #1 (see the sketch). #1 #2 #3 60◦ After passing through polarizer #2 the intensity I2 (in terms of the intermediate intensity I1) is

Answer 1

Step-by-step explanation:

The angle between the polariser 1 and 2 is 60°

If I₁ be the intensity of light after polariser 1 , its intensity after polariser 2 that is I₂ can be expressed as follows

I₂ = I₁ cos² 60

= I₁ x 1/4

= I₁ x
`(1)/(4)`