119k views
0 votes
5.00 L of air at 750 mmHg pressure was compressed into a 3.00 L steel cylinder. What is the final pressure? (round to significant figures)

User JRsz
by
8.3k points

1 Answer

4 votes

Answer:

P2 = 1250mmHg

Step-by-step explanation:

V1 = 5.0L

P1 = 750mmHg

V2 = 3.0L

P2 = ?

According to Boyle's law, the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant.

P = k/V k = P*V

P1*V1 = P2*V2 = P3*V3 =........=Pn*Vn

P1 *V1 = P2 * V2

Solve for P2

P2 = (P1 * V1) / V2

P2 = (750 * 5.0) / 3.0

P2 = 3750 / 3

P2 = 1250mmHg

The final pressure of the gas is 1250mmHg

User Patelify
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.