Question

If 300 mL of water were added to 200 mL solution of 1.8 M H2SO4. What will the concentration of H2SO4 be after the addition of water?​

Answer 1

0.72 M

Step-by-step explanation:

Given data

• Initial volume of the H₂SO₄ solution (V₁): 200 mL

• Volume of water added (VH₂O): 300 mL

• Initial concentration of the H₂SO₄ solution (C₁): 1.8 M

Step 1: Calculate the final volume (V₂)

The final volume of the solution is equal to the sum of the initial volume of the solution and the volume of water.

`V_2 = V_1 + VH_2O = 200 mL + 300mL = 500mL`

Step 2: Calculate the concentration of the diluted solution (C₂)

We will use the dilution rule.

`C_1 * V_1 = C_2 * V_2\\C_2 = (C_1 * V_1)/(V_2) = (1.8M * 200mL)/(500mL)= 0.72 M`