Answer:
Explanation:
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Mean = (697 + 759 + 1266 + 621 + 569 + 432)/6 = 724
Standard deviation = √(summation(x - mean)²/n
n = 6
Summation(x - mean)² = (697 - 724)^2 + (759 - 724)^2 + (1266 - 724)^2+ (621 - 724)^2 + (569 - 724)^2 + (432 - 724)^2 = 415616
Standard deviation = √415616/6 = 263.2
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ ≤ 1000
For the alternative hypothesis,
µ > 1000
It is a right tailed test.
Since the number of samples is small and no population standard deviation is given, the distribution is a student's t. The test statistic, t would be calculated with the formula below
Since n = 6
Degrees of freedom, df = n - 1 = 6 - 1 = 5
t = (x - µ)/(s/√n)
Where
x = sample mean = 724
µ = population mean = 1000
s = samples standard deviation = 263.2
t = (724 - 1000)/(263.2/√6) = - 2.57
We would determine the p value using the t test calculator. It becomes
p = 0.025
From the t distribution table, the critical value is 2.571
Since alpha, 0.05 > than the p value, 0.025, then we would reject the null hypothesis.
Therefore, at a 5% level of significance, the results do not suggest that all of the child booster seats meet the specified requirement.
The results suggests that the safety requirement for the hic measurement should be more than 1000 hic.