Question

What is the total number of moles of solute in 2230 ml of 3.0 M NaOH solution.

Answer 1

6.69 moles

Step-by-step explanation:

Data obtained from the question include:

Volume = 2230mL

Molarity of NaOH = 3 M

First, we'll convert 2230mL to L. This is illustrated below:

1000mL = 1L

2230mL = 2230/1000 = 2.23L

Now, we can obtain the number of mole of NaOH in the solution as follow:

Molarity = mole /Volume

Mole = Molarity x Volume

Mole of NaOH = 3 x 2.23

Mole of NaOH = 6.69 moles

Therefore, the total number of mole of the solute (NaOH) in the solution is 6.69 moles