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4. According to statistics reported on IN-CORP a surprising number of motor vehicles are not covered by insurance. Sample results, consistent with the IN-CORP report, showed 46 of 200 vehicles were not covered by insurance. a. What is the point estimate of the proportion of vehicles not covered by insurance? b. Develop a 95% confidence interval for the population proportion.

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Answer:

a) 0.23

b) The 95% confidence interval for the population proportion is (0.1717, 0.2883).

Explanation:

In a sample with a number n of people surveyed with a probability of a success of
\pi, and a confidence level of
1-\alpha, we have the following confidence interval of proportions.


\pi \pm z\sqrt{(\pi(1-\pi))/(n)}

In which

z is the zscore that has a pvalue of
1 - (\alpha)/(2).

Point estimate

The point estimate is:


\pi = (46)/(200) = 0.23

95% confidence level

So
\alpha = 0.05, z is the value of Z that has a pvalue of
1 - (0.05)/(2) = 0.975, so
Z = 1.96.

The lower limit of this interval is:


\pi - z\sqrt{(\pi(1-\pi))/(n)} = 0.23 - 1.96\sqrt{(0.23*0.77)/(200)} = 0.1717

The upper limit of this interval is:


\pi + z\sqrt{(\pi(1-\pi))/(n)} = 0.23 + 1.96\sqrt{(0.23*0.77)/(200)} = 0.2883

The 95% confidence interval for the population proportion is (0.1717, 0.2883).

User Cesare
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