The diameter of a tennis ball is 2 cm and the diameter of the softball is 1 cm. About how many times as great is the surface area of a half of the tennis ball as to the surface …

Question

asked Jan 26, 2021 148k views

1 Answer

Alvin Theodora · Answer 1 · 2021-02-01T14:44:34+0000

Explanation:

It is given that,

The diameter of a tennis ball is 2 cm and the diameter of the softball is 1 cm. So, radius of tennis ball is 1 cm and radius of softball is 0.5 cm.

Both balls are in the shape of sphere. Half of the balls will becomes hemisphere. The surface area of hemisphere is given by :

$A=2\pi r^2$

Taking ratio of both balls, i.e.

(A_1)/(A_2)=(r_1^2)/(r_2^2)

$(A_t)/(A_s)=(r_t^2)/(r_s^2)\\\\(A_t)/(A_s)=(1^2)/((0.5)^2)\\\\(A_t)/(A_s)=4$

So, the surface area of a half of the tennis ball is 4 times of he surface area of a half of the softball.