Question

What mass of NaOH must be used to prepare 2.5 L of a 0.010 M solution

Answer 1

`m = 1\,g`

Step-by-step explanation:

The molarity is the ratio of the amount of moles solvent to volume of the solute.

`0.010\,M = (0.010\,moles\,NaOH)/(1\,L)`

The quantity of solute is determined by simple rule of three:

`n = \left((2.5\,L)/(1\,L) \right)\cdot (0.010\,mole)`

`n = 0.025\,moles`

The molecular weight of NaOH is
`39.997\,(g)/(mole)`, the mass of solute is:

`m = 1\,g`