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The perimeter of the rectangle is 44. the length is five less than double the width. find the dimensionsThe perimeter of the rectangle is 44. the length is five less than double the width. find the dimensionsThe perimeter of the rectangle is 44. the length is five less than double the width. find the dimensionsThe perimeter of the rectangle is 44. the length is five less than double the width. find the dimensionsThe perimeter of the rectangle is 44. the length is five less than double the width. find the dimensionsThe perimeter of the rectangle is 44. the length is five less than double the width. find the dimensionsThe perimeter of the rectangle is 44. the length is five less than double the width. find the dimensionsThe perimeter of the rectangle is 44. the length is five less than double the width. find the dimensionsThe perimeter of the rectangle is 44. the length is five less than double the width. find the dimensionsThe perimeter of the rectangle is 44. the length is five less than double the width. find the dimensionsThe perimeter of the rectangle is 44. the length is five less than double the width. find the dimensionsThe perimeter of the rectangle is 44. the length is five less than double the width. find the dimensionsThe perimeter of the rectangle is 44. the length is five less than double the width. find the dimensions

User Deniszh
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2 Answers

2 votes

Answer:

The length is 13.

The width is 9.

Explanation:

length = x

width = w

1) x = 2w - 5

2) 44 = 2x + 2w

3) 44 = 2(2w - 5) + 2w

4) 44 = 4w - 10 + 2w

5) 44 = 6w - 10

6) 54 = 6w

7) w = 9

8) x = 2(9) - 5

9) x = 18 - 5

10) x = 13

User Ops
by
4.7k points
5 votes

Answer:

Length = 13

Width = 9

Explanation:

The equation to find the perimeter is 2l+2w=44. The second equation is 2w-5=l since the length is 5 less than double the width.

2l+2w=44,2w-5=l (write equations)

use the equation for length, the second equation, and subtitute it into the first equation's l. Since all l is the same and 2w-5 is equal to l, we can use that equation for the l in 2l+2w=p

2(2w-5)+2w=44 (subtitute)

4w-10+2w=44

6w-10=44 (simplify)

6w=54 (add 10 to both sides)

w=9

use the width to find the length by plugging it into any original equation

2w-5=l

2(9)-5=l

18-5=l

13=l

User Claude Brisson
by
4.8k points