Question

1. An acetic acid solution that is 60.0% HC2H302 (by mass) contains

60.0 g acetic acid and 100.0 g water
60.0 g acetic acid and 40.0 g water
60 moles of acetic acid
60.0 g acetic acid and 60.0 g water

Answer 1

The correct answer is: 60.0 g acetic acid and 40.0 g water

Step-by-step explanation:

The percentage in mass (% by mass) is expressed as follows:

% by mass = % m/m = grams of solute/100 g solution

If the solution of acetic acid is 60.0% by mass, that means that there are 60 grams of solute (acetic acid) in 100 grams of solution. Besides, a solution is composed by solute and solvent (water). If there are 60 grams of solute, there are 40.0 grams of solvent (water) in 100 grams of solution.

So, the solution contains 60.0 g acetic acid and 40.0 g water.