Answer:
-65kJ
Step-by-step explanation:
It is possible to calculate the heat of a reaction by the sum of half-reactions, thus:
(a) A + 2B → C + D ΔH = -20 kJ
(b) B → 2C + D ΔH = -45 kJ
The sum of (a) + (b) gives:
(a) + (b) A + 3B → 3C + 2D ΔH = -20kJ - 45kJ = -65kJ
Thus, heat of reaction is -65kJ