Question

In trapezoid $WXYZ$, $\overline{XY} \parallel \overline{WZ}$, $\angle WXZ = 105^\circ$, $\angle W = 43^\circ$, and $\angle Y = 141^\circ$. Find $\angle YXZ$, in degrees.

Answer 1

32 degrees

Explanation:

The diagram of the problem is drawn and attached.

In Triangle WXZ

105+43+
`\angle WZX`=180 (Sum of Angles in a Triangle)

148+
`\angle WZX`=180

`\angle WZX`=180-148

`\angle WZX`=32 degrees

Since |XY|//|WZ| (parallel to)

`\angle WZX`=
`\angle YXZ` (Alternate Angles)

Therefore:

`\angle YXZ`=32 degrees