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Find the distance between (0,10) and (12,1)

A. 12
B. 11
C. 15
D. 16

Find the distance between (0,10) and (12,1) A. 12 B. 11 C. 15 D. 16-example-1

1 Answer

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9514 1404 393

Answer:

C. 15

Explanation:

The distance formula can be used for this.

d = √((x2 -x1)² +(y2 -y1)²) = √((12 -0)² +(1 -10)²) = √(144 +81) = √225

d = 15

The distance between the points is 15 units.

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Alternate solution

You may recognize that the slope of the line is -3/4, suggesting that this is some multiple of a 3-4-5 right triangle. That multiple is 9/3 = 12/4 = 3, so the hypotenuse of the triangle is 5×3 = 15 units.

User Treasha
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