Question

The number of dogs in a city is declining at a rate of about .08% each

year. If there were 3500 cats to begin with, how many will there be in 10
years?

Answer 1

There will be 3472 cats in 10 years

Explanation:

There were 3500 cats

The number of dogs in a city is declining at a rate of about 0.08% each year.

We are supposed to find the no. of cats in 10 years

Formula :
`N(t)=N_0(1-r)^t`

Where N(t) = Remaining cats after t days

`N_0` = Initial population

r = rate of depreciation

t=time

So, No. of cats remained after 10 years =
`3500(1-(0.08)/(100))^(10)=3472.100`

Hence There will be 3472 cats in 10 years