Question

Two concavemirrors are kept in a straight line as shown in fig. Mirror A forms 2 times enlarged real image of an object kept in front of it on the same straight line. The focal length of mirror A is given as 10cm

i.Using sign conventions calculate the object position and image position in the case of mirror A

Answer 1

Step-by-step explanation:

Mirror formation in mirror A

focal length f = - 10 cm ( concave mirror )

Let u be object distance , v is image distance .

In case image is virtual

v / u = 2

v = 2u

Mirror formula

`(1)/(v) +(1)/(u) =(1)/(f)`

Putting the values

`-(1)/(2u) +(1)/(u) =-(1)/(10)`

`(1)/(2u)` =
`-(1)/(10)`

u = -5 cm

In case image is real

`(1)/(v) +(1)/(u) =(1)/(f)`

`(1)/(2u) +(1)/(u) =-(1)/(10)`

`(3)/(2u) =-(1)/(10)`

u =
`-(30)/(2)`

u = - 15 cm