Question

Lindsay​ Electronics, a small manufacturer of electronic research​ equipment, has approximately 6 comma 500 items in its inventory and has hired Joan​ Blasco-Paul to manage its inventory. Joan has determined that 11​% of the items in inventory are A​ items, 33​% are B​ items, and 56​% are C items. She would like to set up a system in which all A items are counted monthly​ (every 20 working​ days), all B items are counted quarterly​ (every 62 working​ days), and all C items are counted semiannually​ (every 121 working​ days). How many items need to be counted each​ day? The total number of items that need to be counted each day is nothing items ​(round your response to the nearest whole​ number).

Answer 1

The total number of items to be counted each day ≈ 100

Explanation:

Lindsay​ Electronics has 6,500 items in its inventory.

11​% of the items in inventory are A​ items

33% of the items in inventory are B items

56​% of the items in inventory are C items

A items are counted every 20 working​ days

B items are counted every 62 working​ days

C items are counted every 121 working​ days

How many items need to be counted each​ day?

First we will find the number of items of type A, B and C

Number of A​ items = 11​% of 6,500 = 0.11*6500 = 715

Number of B items = 33% of 6,500 = 0.33*6500 = 2145

Number of C items = 56% of 6,500 = 0.56*6500 = 3640

The number of A items to be counted each day is

A items = 715/20

The number of B items to be counted each day is

B items = 2145/62

The number of C items to be counted each day is

C items = 3640/121

The total number of items to be counted each day is

Total items = 715/20 + 2145/62 + 3640/121

Total items = 100.42

Rounding the answer to the nearest whole number yields,

Total items ≈ 100