Question

A circle has the equation x2+12y+22x+y2−167=0.

What is the equation of the circle in standard form?

(x−11)2+(y−6)2=324

(x+11)2+(y+6)2=184

(x−11)2+(y−6)2=184

(x+11)2+(y+6)2=324

Answer 1

`(x + 11)2 + (y + 6)2 = 184`

Answer 2

Answer: The answer would be (x+11)2+(y+6)2=324

Step-by-step explanation: I just got it right on my test :)