Question

A circle has the equation x2+y2+16y−30x=0.

What is the equation of the circle in standard form, the coordinates of its center, and the length of its radius?

The equation of the circle is (x+15)2+(y−8)2=289; the center is at (−15,8), and the radius is 17 units.

The equation of the circle is (x−15)2+(y+8)2=289; the center is at (−15,8), and the radius is 289 units.

The equation of the circle is (x−15)2+(y+8)2=289; the center is at (15,−8), and the radius is 17 units.

The equation of the circle is (x−15)2+(y+8)2=289; the center is at (15,−8), and the radius is 289 units.

Answer 1

Explanation:

hello :

x2+y2+16y−30x=0 means : (x²-30x)+(y²+16y) =0

(x²-30x+15²)-15²+(y²+16y+8²) -8²=0

(x-15)²-225+(y+8)²-64=0

(x-15)²+(y+8)²=289=17²......standard form when the center is (15,- 8)

and radius 17