Question

What would the pressure be if 2.80atm of air is put into a 15.6L fixed volume cylinder and heated from 285K to 396K?

Answer 1

3.89 atm

Step-by-step explanation:

Given data

• Initial pressure (P₁): 2.80 atm

• Initial temperature (T₁): 285 K

• Initial volume (V₁): 15.6 L

• Final pressure (P₂): ?

• Final temperature (T₂): 396 K

• Final volume (V₂): 15.6 L (=V₁)

If we treat air as an ideal gas, we can calculate the final pressure using the Gay-Lussac's law.

`(P_1)/(T_1) = (P_2)/(T_2)\\P_2 = (P_1 * T_2 )/(T_1) = (2.80atm * 396K )/(285K)\\P_2 = 3.89 atm`