Question

Write an equation in slope-intercept line form form for the line perpendicular to 2x-3y=12 that passes through the point (8,5)

Answer 1

3x+2y=34

Explanation:

L1: 2x-3y=12 => the slope m1=-2/(-3)=2/3

L2 perpendicular to L1 => m2= -1/m1= -3/2

the point A(8,5) ∈ L2

=> y–yA=m2(x–xA)

L2: y-5=-3/2 *(x-8)

L2: 2y-10=-3x+24

L2: 3x+2y=34