Question

An artist creates a cone shaped sculpture for an art exhibit. If the sculpture is 8 feet tall and has a base with a circumference of 21.352 feet, what is the volume of the sculpture? Use 3.14 for Pi

Answer 1

Volume,
`V=96.79\ \text{feet}^3`

Explanation:

An artist creates a cone shaped sculpture for an art exhibit.

Height of sculpture is 8 feets

The circumference of base of the cone is 21.352 feet.

The base of a con is circular shaped. So,

`2\pi r= 21.352`

r is radius of cone

`r= (21.352)/(2* 3.14) \\\\r=3.4\ ft`

The volume of cone shaped sculpture is given by :

`V=(1)/(3)\pi r^2 h\\\\V=(1)/(3)* 3.14* (3.4)^2 * 8\\\\V=96.79\ \text{feet}^3`

So, the volume of the sculpture is
`96.79\ \text{feet}^3`.