Question

Which is the equation of a parabola with focus (-5, 3) and vertex (-5, 6)?

a. -12(7-6) = (x+5)
C (x+5)2 =-12(y-6)
b. (+ 5)² = -30(7-6)
d. (x+5)2 = -12(7-6)
Please select the best answer from the choices provided
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Answer 1

Which is the equation of a parabola with focus (-5, 3) and vertex (-5, 6)?

Focus and Vertex are both on x = –5, so that’s the Axis of Symmetry.

Distance from Vertex to Focus is p = 3-6 = –3.

4p(y-k) = (x-h)^2

4(–3)(y–6) = (x-(-5))^2

–12(y–6) = (x+5)^2

y = (–1/12)(x+5)^2 + 6 <== Answer

Distance from Vertex to Directrix is –p = 3.

Directrix is y = 6+3 = 9.

Explanation:

Answer 2

Answer: On edg its C: (x+5)^2 = -12(y-6)

Explanation: