Question

Simply by living, an 87.5 kg human being will consume approximately 20.0 mol of O 2 per day. To provide energy for the human, the O 2 is reduced to H 2 O duing food oxidation by the reaction O 2 + 4 H + + 4 e − − ⇀ ↽ − 2 H 2 O Determine the current generated by the human per day. In this case, the current is defined as the flow of electrons ( e − ) to O 2 from the food the human consumes.

Answer 1

The current generated by the human per day = 89.34 Amperes

Step-by-step explanation:

Given that ;

the human consumes 20.0 mole of O₂ per day

The Food oxidation is given by the reaction :

`O_2 + 4 H^+ + 4 e^- ----> 2H_2O`

So; the human will produce 20.0 × 4 moles of e⁻

Thus; moles of e⁻ produced is = 80

Charge on 1 e⁻ = 1.602 × 10⁻¹⁹ C

e⁻ in 1 mole = 6.023 × 10²³

The total charge per day =
`(1.602*10^(-19)*6.023*10^(23)*80)/(24*60*60)`

= 89.34 Amperes