A 40 g sample of water at an inital temperature of 40°C is heated to 99°C. How much heat did the water absorb? The specific heat of water is 4.18J/gºC a. 413.82j b.-9864j c.9864.8j d.-413.82j

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asked Jan 27, 2021 36.1k views

4 votes

A 40 g sample of water at an inital temperature of 40°C is heated to 99°C. How much heat did the water absorb? The specific heat of water is 4.18J/gºC

a. 413.82j
b.-9864j
c.9864.8j
d.-413.82j

Chemistry
high-school

Fraff asked

by Fraff

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1 Answer

6 votes

Answer:

Step-by-step explanation:

Q = mcΔt°

Q = 40g * 4.18 J/g*°C *(99°C - 40°C) = 9864.8 J

Philip Claren answered Jan 31, 2021

by Philip Claren

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