Question

What mass of aluminum at 144 Celsius will increase the temperature of 100 g of water by from 10 C to 15 C?

aluminum s = 0.900 water s = 4.184

Answer 1

`m_(Al) = 18.019\,g`

Step-by-step explanation:

There is a heating process between an aluminium piece and water, which is described by the First Law of Thermodynamics:

`Q_(Al) = - Q_(w)`

`m_(Al)\cdot c_(Al)\cdot (T_(o,Al)-T) = m_(w)\cdot c_(w)\cdot (T-T_(o,w))`

The mass of the aluminium piece is therefore cleared and known variables are substituted:

`m_(Al) = (m_(w)\cdot c_(w)\cdot (T-T_(o,w)))/(c_(Al)\cdot (T_(o,Al)-T))`

`m_(Al) = ((100\,g)\cdot \left(4.184\,(J)/(g\cdot^(\circ)C) \right)\cdot (15^(\circ)C-10^(\circ)C))/(\left(0.900\,(J)/(g\cdot ^(\circ)C) \right)\cdot (144^(\circ)C-15^(\circ)C))`

`m_(Al) = 18.019\,g`