Question

Ken wants to build a table and put a border around it. The table and border must have an area of 3,276 square inches. The table is 36 inches wide and 72 inches long without the border. Which quadratic equation can be used to determine the thickness of the border, x? (2 points)

Group of answer choices

4x2 + 216x + 2,592 = 0

4x2 + 216x − 684 = 0

2x2 + 216x − 3,276 = 0

x2 + 108x + 3,276 = 0

Answer 1

4x2+216x-684x

Explanation:

solnA) The dimensions of the table are in inches

Let

x=the thickness of the border

we know that the table and the border must have an area of 3,276 square feet

convert the dimensions of the table to feet

remember that; 1ft =12in

36in=3ft

72in=6ft

i.e; 3,276 = (6+12x)*(3+2x)

solve for x

3276=6×3+ 6×2x +2x×3+ 4x²

3276=18+12x+6x+4x²

4x²+18x+18-3276=0

4x²+18x-3258

solnB) The dimensions of the table are in feet

Let

x=the thickness of the border

we know that the table and the border must have an area of 3,276 square feet

i.e 3,276 = ()×()

solve for x

3,276 = 72×36 + 72×2x + 2x×36 + 4x²

3,276 = 2,592 + 144x + 72x + 4x²

4x² + 216x + 2,592 + 3276 = 0

4x²+216× - 684= 0

therefore; the quadratic equation can be used to determine the thickness of the border =

4x² + 216x - 684 = 0