Question

The Smithsonain used to have a huge pendulum that was 21.0 m long. What was its period?

Answer 1

T = 9.19 seconds

Step-by-step explanation:

It is given that,

Length of the pendulum, l = 21 m

We need to find its time period. We know that the time period of the pendulum is given by :

`T=2\pi \sqrt{(L)/(g)}`

g is acceleration due to gravity

So,

`T=2\pi \sqrt{(21)/(9.8)}\\\\T=9.19\ s`

So, the period of the pendulum is 9.19 seconds.