Question

A. What is the Gibbs free energy for this reaction at 298 K?

2NH3(g) N2(g) + 3H2(g)

ΔH = 91.8 kJ

ΔS = 0.1987 kJ/K


Is the reaction spontaneous at 298 K (room temperature)? (3 points)

Answer 1

the reaction is spontaneous

Step-by-step explanation:

Answer 2

32.6 Jmol-1

Step-by-step explanation:

Now we have to use the formula

∆G= ∆H-T∆S where

∆G= change in free energy (the unknown)

∆H= enthalpy change = 91.8KJ

∆S= entropy change= 0.1987 kJ/K

T= temperature= 298K

∆G= 91.8 - (298× 0.1987)

∆G= 91.8 - 59.2126

∆G= 32.6 Jmol-1