Question

Jennifer scores a 77 on her algebra 2 test. The mean on the test was 73. The standard deviation on the test was 5. What was her Z-score

Answer 1

0.80

Explanation:

The z-score is found from the formula ...

Z = (X -μ)/σ

Z = (77 -73)/5 = 4/5 = 0.80

Jennifer's Z-score was 0.80.