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Given the equation of the parabola -36y = x^2 The focus of the parabola is

Given the equation of the parabola -36y = x^2 The focus of the parabola is
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Given the equation of the parabola -36y = x^2 The focus of the parabola is

User Fatemeh Asgarinejad
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1 Answer

5 votes
(0,-9) or -x2/36,,,, -x2 on top
User Origin
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