Question

how many grams of ammonium carbonate are needed to decompose in order to produce 6.52 g of carbon dioxide?

Answer 1

= 14.24g of
`(NH4)_(2)CO_(3)` is required.

Step-by-step explanation:

Reaction equation:

`(NH4)_(2)CO_(3)` →
`2NH_(3) + CO_(2) + H_(2) O`

Mole ratio of ammonium carbonate to carbon dioxide is 1:1

1 mole of CO2 - 44g

?? mole of CO2 - 6.52g

= 6.52/44 = 0.148 moles was produced from this experiment.

Therefore, if 1 mole of
`(NH4)_(2)CO_(3)` - 96.09 g

0.148 mol of
`(NH4)_(2)CO_(3)` -- ?? g

=0.148 × 96.09

= 14.24g of
`(NH4)_(2)CO_(3)` is required.