Question

the eight bytes in the words y and z. If a byte is the code for a decimal number, output it to the console. Otherwise, simply ignore it and examine the next byte. The program must be a loop. That means that you must write a loop that will execute eight times to examine each byte, output if necessary, and continue. End the program as usual with a syscall 10. After completing the program answer this question: What numbers are output?

Answer 1

See explaination

Step-by-step explanation:

MIPS PROGRAM :-

.data

y: .word 0x32774b33

z: .word 0x2a276c39

y_prompt: .asciiz "Y= "

z_prompt: .asciiz "Z= "

new_line: .asciiz "\\"

.text

main:

la $s0, y

la $s1, z

li $t0, 8

loop:

beqz $t0, END_OF_LOOP

# checking fo y word

lb $t1, 0($s0)

#checking for whether the byte is decimal or not

li $t2, '0'

bltu $t1, $t2, check_for_z

li $t2, '9'

bltu $t2, $t1, check_for_z

#print new line

li $v0, 4

la $a0, new_line

syscall

#print y prompt

li $v0, 4

la $a0, y_prompt

syscall

#print the value

li $v0, 1

add $a0, $zero, $t1

syscall

check_for_z:

# checking fo z word

lb $t1, 0($s1)

#checking for whether the byte is decimal or not

li $t2, '0'

bltu $t1, $t2, next_element

li $t2, '9'

bltu $t2, $t1, next_element

#print new line

li $v0, 4

la $a0, new_line

syscall

#print y prompt

li $v0, 4

la $a0, z_prompt

syscall

#print the value

li $v0, 1

add $a0, $zero, $t1

syscall

next_element:

addi $s0, $s0, 1

addi $s1, $s1, 1

#decrease the counter

addi $t0, $t0, -1

j loop

END_OF_LOOP:

li $v0,10

syscall