Question

A solenoid has an internal magnetic field of 0.28T. What is the energy density of the field?

Answer 1

Energy density,
`E=3.11* 10^4\ J`

Step-by-step explanation:

It is given that,

Magnetic field in a solenoid is 0.28 T

We need to find the energy density of the field. The energy density of the magnetic field is given by below formula as follows :

`E=(B^2)/(2\mu_o)\\\\E=((0.28)^2)/(2* 4\pi * 10^(-7))\\\\E=3.11* 10^4\ J`

So, the energy density of this field is
`3.11* 10^4\ J`.