Answer:
2x^2+4x-2 = 2 * (x - 1 -) * (x - 1 + )
Explanation:
Factor completely 2x^2+4x-2
2x^2+4x-2 = 2* (x^2 + 2x - 1)
x = 1 + root( 4 - 4*(-1))/2
x = 1 + root(2)
and x = 1 - root(2)
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) * (x - 1 + )