Answer:
No, the distance from (0, 0) to (2, √6) is not 3 units.
Explanation:
In the figure attached, the problem is shown clearly.
Distance formula:
√[(x2 - x1)² + (y2 - y1)²]
Distance between (0, 0) and (3, 0)
√[(3 - 0)² + (0 - 0)²] = 3
Then, a point lies on the circle shown if the distance between it and center is 3.
Distance between (0, 0) and (2, √6)
√[(2 - 0)² + (√6 - 0)²] = √[4 + 6] = √10 ≠ 3