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What pressure in kPa is exerted by 2.150 mol of Co, at 57.00 °C in 0.7500 L?!​

User Nemec
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1 Answer

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This is an ideal gas law question. Use the equation PV =nRT.
P(0.75) = (2.150)(0.08206)(273+57)
P = 77.63atm
The answer needs to be in kPa and theres 101.325kpa per 1atm, so
77.63*101.325 = 7865.73 kPa
If youre supposed to have 3 significant figures, then 7870kPa
User Curvegraph
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