Answer:
Given:
Sample size, n = 640
Since result showed that 99.2% of them would erase all of their personal information online if they could, we have:
P' = 99.2% = 0.992
Let's take p = 50%
Our null and alternative hypothesis will be :
H0 : u = 0.5
H1 : u > 0.5
In this case we are to check for the test statistic.
![(P' - p)/(√(p(1-p)/n))](https://img.qammunity.org/2021/formulas/mathematics/high-school/kv20e847y1o0uxahhperzzynrflpc53ojb.png)
![= (0.992 - 50)/(√(50(1-50)/640))](https://img.qammunity.org/2021/formulas/mathematics/high-school/7qssf1klog4w5rf30xci6ewlr42qpxdpdc.png)
= 24.9
Test statistic, Z = 24.893
In conclusion, the results are significantly high, which suggets there is suffcient evidence to support the claim that most adults would erase all of their personal information online.