Answer:
projectile motion
Explanation:
If the initial velocity v0 is allowed to be zero, here is one:
You are standing next to a very deep hole, and wonder what is the depth h? You drop a stone into the hole, and hear a delayed sound (of the stone hitting the bottom) after time T on your stopwatch. Given the gravitational constant g, given the speed of sound c, and by ignoring air-resistance on the stone, calculate the depth h.
Solution:
h = cT+c2g[1−1+2gTc−−−−−−−√].