Question

A 4.44 L container holds 0.481 mol of O2 at 22.6 0C. What is the pressure of the tank?

Answer 1

2.63 atm.

Step-by-step explanation:

Given,

Volume,V = 4.44 L

n = 0.481 mol of O₂

Temperature, T = 22.6°C = 22.6 + 273 = 295.6 K

Using ideal gas law

`P = (nRT)/(V)`

`P = (0.481* 0.0821 * 295.6)/(4.44)`

P = 2.63 atm.

Pressure of the tank is equal to 2.63 atm.