Question

At a carnival game, you may win an inflatable crayon, you may win a small stuffed animal, or you may win nothing at all. If the probability of winning nothing is 0.67 and the probability of winning a small stuffed animal is 0.27, what is the probability of winning an inflatable crayon? Express your answer as a decimal.

Answer 1

Answer: 0.06

Explanation:

Since we only care about winning the inflatable crayon, it is unimportant whether nothing is won or a small stuffed animal is won, just that the outcome is determined by subtracting all of the possible outcomes given from the probability of winning nothing and the probability of winning a stuffed animal. Given that the total probability of all outcomes of the event is 1, we can conclude that the probability of winning an inflatable crayon is:

`P(\text{not winning inflatable crayon}) = P(\text{All Outcomes}) - P(\text{winning nothing})`

`- P(\text{winning a small stuffed animal)}`

`P = 1-0.67-0.27 \\ = 0.06 \ $or 6\%`