Question

A GAS SAMPLE HAS A TEMPERATURE OF 18 CELSIUS WITH AN UNKNOWN VOLUME. THE SAME GAS HAS A VOLUME OF 436 ML WHEN THE TEMPERATURE IS 91 CELSIUS WITH NO CHANGE IN THE PRESSURE AND AMOUNT OF GAS

WHAT WAS THE INITIAL VOLUME IN MILLILITERS OF THE GAS

Answer 1

349 mL

Step-by-step explanation:

Given data

• Initial volume (V₁): unknown

• Initial temperature (T₁): 18 °C + 273.15 = 291 K

• Final volume (V₂): 436 mL

• Final temperature (T₂): 91°C + 273.15 = 364 K

If we consider the has as an ideal gas, we can calculate the initial volume of the gas sample using the Charles' law.

V₁ / T₁ = V₂ / T₂

V₁ = V₂ × T₁ / T₂

V₁ = 436 mL × 291 K / 364 K = 349 mL