Question

A 55W light bulb will allow 0.5A to flow through it. If the outlet provides a potential difference of 110V, how much resistance is provided by the bulb?

Answer 1

Step-by-step explanation:

110=0.5×R

R=220 ohms

resistance of the light bulb=220 ohms

Answer 2

Answer: resistance = 220 ohms

Explanation: given that

Power P = 55W

Current I = 0.5A

Potential difference V = 110V,

Using the formula

P = IV =V^2/R

55 = 110^2/R

R = 12100/ 55

R = 220 ohms