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A 2 L container contains 5 moles of helium gas at 0.5 atm. What is the
temperature of the gas?

User Ivoszz
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1 Answer

1 vote

Answer:

2.44 K IS THE TEMPERATURE OF THE GAS

Step-by-step explanation:

PV = nRT

P = 0.5 atm

V = 2 L

n = 5 moles

R = 0.082 L atm mol^-1 K^-1

T = ?

Substituting for T in the equation, we obtain:

T = P V / nR

T = 0.5 * 2 / 5 * 0.082

T = 1 / 0.41

T = 2.44 K

The temperature of the gas is 2.44 K

User John Riselvato
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