Question

A clown is shot out of cannon with a velocity of 200 feet per second at an angle of 24°

with the horizontal. Find the vertical and horizontal components of the velocity of this clown.

Answer 1

Vertical component of velocity is
`81.35 ft/sec.`

Horizontal component of velocity is
`182.6 ft/sec`.

Explanation:

Horizontal component of velocity is defined as:

`v_(x) = v* cos\theta`

Vertical component of velocity is defined as:

`v_(y) = v* sin\theta`

Where
`v_(x) , v_(y)` are the horizontal and vertical components of velocity.

`v` is the actual velocity and

`\theta` is the angle with horizontal axis at which the object was thrown.

Here, we are provided with the following:

`v = 200 ft/sec`

`\theta = 24^\circ`

`v_(x) = 200 * cos24^\circ\\\Rightarrow 200 * 0.913\\\Rightarrow v_(x) = 182.6 ft/sec`

`v_(y) = 200 * sin24^\circ\\\Rightarrow 200 * 0.407\\\Rightarrow v_(y) = 81.35 ft/sec`

So, Vertical component of velocity is
`81.35 ft/sec.`

Horizontal component of velocity is
`182.6 ft/sec`.